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This page uses a lot of Greek symbols. The font is SPIONIC.TTF and is available for free download here. You will also need a bit of familiarity with very basic calculus and vector algebra. The idea of the magnetic moment is pretty simple and comes from some basic observations of the physical nature of electric currents and magnetic fields. The most basic observation is that a charge, q, moving through a magnetic field, B, with velocity, v experiences a force, F, which is directed at right angles to both v and B. ![]() This is, of course, a vector cross-product from which we can get the magnitude of F quite easily: F = qvBsin(
where dF = dq(vXB)
and since v represents the movement of charge per unit time, dl/dt, we can write: dF = (dq/dt)(dlXB)
If you integrate over the length of the wire to get the total force of the current: F = i(lXB)
(i = dq/dt) Now, if l and B are at right angles to each other then we can calculate the magnitude of F: F = ilB (
where i is the current, l is the length of the wire and B is the magnitude of the magnetic field. Now, imagine a current conducting coil in a magnetic field at an angle, ![]() The first diagram is a side view of the coil and the second is a top view. Here, the field, B, in the second diagram is directed away from the viewer into the page as indicated by the x's. The current carrying coil is rectangular in shape with sides of length a and b. The force, F, is then given by: F = iaB
and: F' = ibBsin(
Forces F' on sides b cancel each other out but forces F constitute a torque: The torque, iA is referred to as the magnetic moment and is symbolised with the greek letter The vector version of this equation is: where Note that in this case the torque and the angular momentum are colinear. When this is not the case the rotational system executes a somewhat more complex precessional motion. Consider the rotating top: ![]() In this case the torque, So, rather than a change in the magnitude of the angular momentum as in the case of the coil, the direction of the angular momentum changes. The top precesses about the pivot point. You're familiar with this effect if you have ever played with a child's top. The top is spun up to speed, let go at which point it begins to 'wobble' or precess, due the force of gravity. The z-component of the spin magentic moment is proportional to the z-component of the spin angular momentum: = qv
(i = q/t, A = = (q/2m)mvr
=(q/2m)Lz
(q/2m) is often replaced with When the spin magnetic moment of a particle such as, oh ... a nucleus let's say, finds itself in a magnetic field acts much as the child's top does in a gravitational field. The magnetic moment precesses about the magnetic field. How fast, you ask? Depends on the field strength and the nucleus. (from basic physics ... look it up) dL =
=
and, using the proportionality between
d
=
![]() Also: d
=
(from above) so that: d
or: We can calculate the Larmor frequency of a proton with = 3.143 x 109s-1
= 500.3 MHz
That's how fast! A magnet of this field strength is usually referred to as a 500 MHz magnet rather than its 11.75 Tesla field strength and in general, the approximate Larmor frequency of protons in a magnet's field is refered to as the magnet's 'field'. The energy of a magnetic moment can be worked out by considering the action of a torque on the magnetic moment, as in an external magnetic field, B. For the coil example above, the torque rotates the coil and hence, the magnetic moment towards the direction of the field and in the process does work. The potential energy of the coil depends on the angle that it's magnetic moment makes with the field. We can come up with an analytical expression for this by integrating the angular momentum expression: dW =
(basic physics by analogy with W = Fs) ( W = ∫
= ∫
=
If we arbitrarily take the E = -
or in dot-product vector notation:
E = -
Amazingly, I have never seen this explicitly derived in any textbook ... frequently the result is simply stated. Yet this is needed to build the Hamiltonian for the quantum mechanical description of the behaviour of magnetic moments!! Also, if we integrate over the range The Hamiltonian is constructed from the above energy equation: where B0 is the field along the z-axis. |
