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Application of an rf field at right angles to the external field results in changes that are difficult to picture clearly unless one invokes the rotating frame of reference. You need a bit of vector algebra for the explanation. We start in the laboratory frame. Picture yourself standing and watching a rotating vector: ![]() The vector, F, rotates with angular velocity dF/dt =
Note that I am using d/dt for the laboratory frame and ∂/∂t for the rotating frame. If we now 'jump' on to the rotating frame and look at the vector, it will appear to be motionless: ![]() and we can say, that from our point of view in the rotating frame: ∂F/∂t = 0
Now, let's turn it around. Let's suppose that there is vector, G, that appears motionless in the laboratory frame: ![]() dG/dt = 0
If we view this vector from the rotating frame, which is rotating at angular frequency ![]() ∂G/∂t = -
Ok. So far so good. Now let's look at vector G from the rotating frame but this time G is moving in both the laboratory frame and the rotating frame. From our rotating frame viewpoint it will have its - ∂G/∂t = -
or: ∂G/∂t = GX
This is the general transformation equation from laboratory to rotating frame coordinates. Remember that d/dt refers to the laboratory frame and ∂/∂t refers to the rotating frame of coordinates. Now, since we are interested in what is happening to the spin magnetic moment, if we put this into the equation we get: ∂
or: ∂
This has the same form as the expression for the laboratory frame magnetic moment: d
if we replace B with the effective field, Beff = B + ∂
We can choose any angular frequency that we like for the rotating coordinate frame but let's see what happens if we choose ∂
Thus, the magnetic moment vector in the rotating frame is motionless if we choose the proper rotational frequency for the rotating frame. This turns out to be a very happy result for us. If we are in a rotating frame which has a rotational frequency of |